NCERT Class 8 Math Exercise 2.3 Solution of Chapter 2 Linear Equations in one Variable with explanation. Here we provide Class 8 Maths all Chapters in Hindi for cbse, HBSE, Mp Board, UP Board and some other boards.
Also Read : – Class 8 Maths NCERT Solution
NCERT Class 8 Maths Chapter 2 Linear Equations in one Variable Exercise 2.3 Solution in english Medium.
Class 8 Maths Chapter 2 Exercise 2.3 Solution
Q.1. Solve the following equations and check your results.
1. 3x = 2x + 18
Solution:
3x = 2x + 18
3x – 2x = 18
x = 18
Hence x = 18 is the required solution.
Checking result
Putting x = 18, we have
LHS
3x = 3 × 18 = 54
RHS
2x + 18 = 2 × 18 + 18 = 54
LHS = RHS
Hence verified.
2. 5t – 3 = 3t – 5
Solution:
5t- 3 = 3t – 5
5t – 3t = -5 + 3
2t = -2
t = -2/2
t = -1
Hence t = -1 is required solution.
Checking result
Putting t = -1 , we have
LHS
5t – 3 = -8
RHS
3t – 5 = -8
LHS = RHS
Hence verified.
3. 5x +9 = 5 + 3x
Solution:
5x + 9 = 5 + 3x
5x – 3x = 5 – 9
2x = -4
x = -4/2
x = -2
Hence, x = -2 is required solution.
Checking result
Putting x = -2 , we have
LHS
5x + 9 = 5 × (-2) + 9 = -1
RHS
3x + 5 = 3 × (-2) + 5 = -1
LHS = RHS
Hence verfied.
4. 4z + 3 = 6 + 2z
Solution:
We have,
4z + 3 = 6 + 2z
4z – 2z = 6 – 3
2z = 3
z = 3/2
Hence z = 3/2 is required solution.
Checking result
Putting z = 3/2
LHS
4z + 3 = 4(3/2) + 3 = 9
RHS
6 + 2z = 6 + 2(3/2) = 9
LHS = RHS
Hence verified.
5. 2x -1 = 14 – x
Solution:
We have,
2x – 1 = 14 – x
2x + x – 1 = 14
3x = 14 + 1
3x = 15
x = 15/3
x = 5
Hence x = 5 is required solution.
Checking result
Putting x = 5 , we have
LHS
2x – 1 = 2 × 5 – 1 = 9
RHS
14 – x = 14 – 5 = 9
LHS = RHS
Hence verified.
6. 8x + 4 = 3(x – 1) + 7
Solution:
We have 8x + 4 = 3(x – 1) + 7
8x + 4 = 3x – 3 +7
8x + 4 = 3x + 4
8x – 3x + 4 = 4
5x = 4 – 4
5x = 0
x = 0
Hence x = 0 is required solution.
Checking result
Putting x = 0
LHS
8x + 4 = 8 × 0 + 4 = 4
RHS
3(x – 1) + 7= 3(0-1) + 7 = 4
LHS = RHS
Hence verified.
7. x = 4/5(x + 10)
Solution:
We have, x = 4/5(x + 10)
5x = 4(x + 10)
5x = 4x + 40
5x – 4x = 40
x = 40