NCERT Class 6 Math Exercise 1.2 Solution of Chapter 1 Knowing Our Numbers with explanation. Here we provide Class 6 Maths all Chapters in Hindi for cbse, HBSE, Mp Board, UP Board and some other boards.

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NCERT Class 6 Maths Chapter 1 Knowing our Numbers Exercise 1.2 Solution in english Medium.

**Class 6 Maths Chapter 1 Exercise 1.2 Solution**

**Q.1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812,2050 and 2751. Find the total number of tickets sold on all the four days.**

**Ans. **Total number of tickets sold on all the four days

= 1094 + 1812 + 2050 + 2751

=7,707 tickets.

**Q.2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?**

**Ans.** Number of runs he required to complete 10,000 is

= 10,000 – 6,980

= 3,020 runs.

**Q.3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?**

**Ans.** Margin by which successful candidate wins to nearest rival is

= 5,77,500 – 3,48,700

= 2,28,800 votes.

**Q.4. Kirti bookstore sold books worth Rs.2,85,891 in the first week of June and books worth Rs. 4,00,768 in second week of the month . How much was the sale for the two weeks together? In which week was the sale greater and by how much ?**

**Ans.** Total sale of two weeks of june is

= 2,85,891 + 4,00,768

= 6,86,659

In week second sale was greater.

Difference in two sales is

= 4,00,768 – 2,85,891

= Rs. 1,14,877

**Q. 5. Find the difference between the greatest and the least 5- digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.**

**Ans.** Greatest number possible using these digits once = 76,432

Smallest number possible using these digits once = 23,467

Difference between greatest and smallest / least number is

= 76,432 – 23,467

= 52,965.

**Q.6. A machine, on an average , manufactures 2,825 screws a day. How many screws did it produces in the month of January 2006.**

**Ans.** Number of days in January 2006 = 31 days.

Number of screws produced in one day

= 2,825.

therefore

Number of screws produced in 31 days is

= 31 × 2825

= 87,575 screws.

**Q. 7. A merchant had Rs. 78,592 with her. She placed an order for purchasing 40 radio sets at Rs. 1200 each . How much money will remain with her after the purchase?**

**Ans.** Total cost of radio sets is

= 40 × 1200

= 48,000.

Total Money remained after purchasing 40 radio sets is

= 78,592 – 48,000

= Rs. 30,592.

**Q. 8. A student multiplied 7236 by 65 instead ****of multiplying by 56. By how much was his answer greater than the correct answer?**

**Ans.** Actual number = 7236 × 56

Greater Number after multiplying by 65 = 7236 × 65.

Therefore

The answer greater than correct answer is

= 7236 × 65 – 7236 × 56

= 7236( 65 – 56 )

= 7236 × 9

= 65,124.

**Q. 9. To stitch a shirt, 2m 15cm cloth is needed. Out of 40m cloth, how many shirts can be stitched and how much cloth will remain?**

**Ans.** Total cloth available = 40 × 100 = 40000cm as (1m = 100cm )

Cloth required to stitch a shirt = 215cm

Therefore number of shirts can be stitched by using 40000cm cloth is

= 40000÷215

= 18 shirts and 130 cm remains

= 18 shirts and 1m, 30cm cloth remains.

**Q. 10. Medicine is packed in boxes, each weighing 4kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800kg?**

**Ans.** Total load carry capacity of van in gram

= 800 × 1000g

Load of each box = 4500g

Therefore number of boxes can be loaded in this van

= ( 800 × 1000) ÷ 4500

= 177 boxes.

**Q.11. The distance between the school and a student’s house is 1km 875m. Everyday she walks both ways. Find the total distance covered by her in six days.**

**Ans.** Distance covered in one day by her in m

= 1875 × 2 = 3750m

Total distance covered by her in six days

= 3750 × 6

= 22,500m

= 22km 500m ( as 1km= 1000m )

**Q.12. A vessel has 4 litres and 500ml of curd . In how many glasses, each of 25ml capacity can it be filled?**

**Ans.** Total capacity of vessel in ml = 4500ml

Capacity of each glass= 25ml

Therefore

Total number of glasses can be filled each of 25ml from vessel of capacity 4500ml is

= 4500 ÷ 25

= 180 glasses.