NCERT Class 6 Math Exercise 3.1 Solution of Chapter 3 Playing with Numbers with explanation. Here we provide Class 6 Maths all Chapters in Hindi for cbse, HBSE, Mp Board, UP Board and some other boards.

**Also Read : – Class 6 Maths NCERT Solution**

NCERT Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.1 Solution in english Medium.

**Class 6 Math Chapter 3 Exercise 3.1 Solution**

**Q.1. Write all the factors of the following numbers:**

**A. 24**

**Ans. **24 = 1×24

24 = 2×12

24 = 3×8

24 = 4×6

24 = 6×4

Stop here since 4 and 6 have occurred earlier.

Hence, the factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24

**B. 15**

**Ans.**

15 = 1×15

15 = 3×5

15 = 5×3

Stop here since 3 and 5 have occurred earlier.

Hence, the factors of 15 are 1, 3, 5, 15.

**C. 21**

**Ans.**

21 = 1×21

21 =3×7

21 =7×3

Stop here since 3 and 7 have occurred earlier.

Hence, the factors of 21 are 1, 3, 7, 21.

**D. 27**

**Ans.**

27 = 1×27

27 =3×9

27 =9×3

Stop here since 3 and 9 have occurred earlier.

Hence, the factors of 27 are 1, 3, 9, 27.

**E. 12**

**Ans.**

12 = 1×12

12 = 2×6

12 = 3×4

12 = 4×3

Stop here since 3 and 4 have occurred earlier.

Hence, the factors of 12 are 1, 2, 3, 4, 6, 12

**F. 20**

**Ans.**

20 = 1×20

20 = 2×10

20 = 4×5

20 = 5×4

Stop here since 4 and 5 have occurred earlier.

Hence, the factors of 20 are 1, 2, 4, 5, 10, 20.

**G. 18**

**Ans.**

18 = 1×18

18 = 2×9

18 = 3×6

18 = 6×3

Stop here since 3 and 6 have occurred earlier.

Hence, the factors of 18 are 1, 2, 3, 6, 9, 18.

**H. 23**

**Ans.**

23 = 1×23

23 = 23×1

Stop here since 1 and 23 have occurred earlier.

Hence, the factors of 23 are 1, 23.

**I. 36**

**Ans.**

36= 1×36

36= 2×18

36= 3×12

36= 4×9

36= 6×6

Stop here since 6 and 6 are same.

Hence, the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.

**Q.2. Write first five multiples of:**

**A. 5**

**Ans.** The required multiples are :

5×1 = 5

5×2 = 10

5×3 = 15

5×4 = 20

5×5 = 25

Hence, the first five multiples of 5 are 5, 10, 15, 20, 25.

**B. 8**

**Ans. **The required multiples are :

8×1 = 8

8×2 = 16

8×3 = 24

8×4 = 32

8×5 = 40

Hence, the first five multiples of 8 are 8, 16, 24, 32, 40.

**C. 9**

**Ans.** The required multiples are :

9×1 = 9

9×2 = 18

9×3 = 27

9×4 = 36

9×5 = 45

Hence, the first five multiples of 9 are 9, 18, 27, 36, 45 .

**Q.3. Match the items in column 1 with the items in column 2.**

Column 11. 35 2. 15 3. 16 4. 20 5. 25 | Column 2A. Multiple of 8 B. Multiple of 7 C. Multiple of 70 D. Factor of 30 E. Factor of 50 F. factor of 20 |

**Ans.** 1 – B

2 – D

3 – A

4 – F

5 – E

**Q.4. Find all the multiples of 9 upto 100.**

**Ans.** All the multiples of 9 upto 100 are as :

9×1 = 9

9×2 = 18

9×3 = 27

9×4 = 36

9×5 = 45

9×6 = 54

9×7 = 63

9×8 = 72

9×9 = 81

9×10 = 90

9×11 = 99

Hence, all the multiples of 9 upto 100 are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.