Class 6 Maths Chapter 3 Exercise 3.1 Solution – Playing With Numbers NCERT

NCERT Class 6 Math Exercise 3.1 Solution of Chapter 3 Playing with Numbers with explanation. Here we provide Class 6 Maths all Chapters in Hindi for cbse, HBSE, Mp Board, UP Board and some other boards.

Also Read : – Class 6 Maths NCERT Solution

NCERT Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.1 Solution in english Medium.

Class 6 Math Chapter 3 Exercise 3.1 Solution


Q.1. Write all the factors of the following numbers:


A. 24
Ans. 24 = 1×24

24 = 2×12

24 = 3×8

24 = 4×6

24 = 6×4

Stop here since 4 and 6 have occurred earlier.

Hence, the factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24


B. 15
Ans.

15 = 1×15

15 = 3×5

15 = 5×3

Stop here since 3 and 5 have occurred earlier.

Hence, the factors of 15 are 1, 3, 5, 15.

 


C. 21
Ans.

21 = 1×21

21 =3×7

21 =7×3

Stop here since 3 and 7 have occurred earlier.

Hence, the factors of 21 are 1, 3, 7, 21.

 


D. 27
Ans.

27 = 1×27

27 =3×9

27 =9×3

Stop here since 3 and 9 have occurred earlier.

Hence, the factors of 27 are 1, 3, 9, 27.


E. 12
Ans.

12 = 1×12

12 = 2×6

12 = 3×4

12 = 4×3

Stop here since 3 and 4 have occurred earlier.

Hence, the factors of 12 are 1, 2, 3, 4, 6, 12

 


F. 20
Ans.

20 = 1×20

20 = 2×10

20 = 4×5

20 = 5×4

Stop here since 4 and 5 have occurred earlier.

Hence, the factors of 20 are 1, 2, 4, 5, 10, 20.

 


G. 18
Ans.

18 = 1×18

18 = 2×9

18 = 3×6

18 = 6×3

Stop here since 3 and 6 have occurred earlier.

Hence, the factors of 18 are 1, 2, 3, 6, 9, 18.

 


H. 23
Ans.

23 = 1×23

23 = 23×1

Stop here since 1 and 23 have occurred earlier.

Hence, the factors of 23 are 1, 23.


I. 36
Ans.

36= 1×36

36= 2×18

36= 3×12

36= 4×9

36= 6×6

Stop here since 6 and 6 are same.

Hence, the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.


Q.2. Write first five multiples of:


A. 5
Ans. The required multiples are :

5×1 = 5

5×2 = 10

5×3 = 15

5×4 = 20

5×5 = 25

Hence, the first five multiples of 5 are 5, 10, 15, 20, 25.


B. 8
Ans. The required multiples are :

8×1 = 8

8×2 = 16

8×3 = 24

8×4 = 32

8×5 = 40

Hence, the first five multiples of 8 are 8, 16, 24, 32, 40.


C. 9
Ans. The required multiples are :

9×1 = 9

9×2 = 18

9×3 = 27

9×4 = 36

9×5 = 45

Hence, the first five multiples of 9 are 9, 18, 27, 36, 45 .


Q.3. Match the items in column 1 with the items in column 2.

Column 1
1. 35
2. 15
3. 16
4. 20
5. 25
Column 2
A. Multiple of 8
B. Multiple of 7
C. Multiple of 70
D. Factor of 30
E. Factor of 50
F. factor of 20

Ans. 1 – B
2 – D
3 – A
4 – F
5 – E


Q.4. Find all the multiples of 9 upto 100.
Ans. All the multiples of 9 upto 100 are as :

9×1 = 9

9×2 = 18

9×3 = 27

9×4 = 36

9×5 = 45

9×6 = 54

9×7 = 63

9×8 = 72

9×9 = 81

9×10 = 90

9×11 = 99

Hence, all the multiples of 9 upto 100 are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.


 

Leave a Comment