# Class 6 Maths Chapter 3 Exercise 3.6 NCERT Solution – Playing With Numbers

NCERT Class 6 Math Exercise 3.6 Solution of Chapter 3 Playing with Numbers with explanation. Here we provide Class 6 Maths all Chapters in Hindi for cbse, HBSE, Mp Board, UP Board and some other boards.

Also Read : – Class 6 Maths NCERT Solution

NCERT Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.6 Solution in english Medium.

## Class 6 Maths Chapter 3 Exercise 3.6 Solution

Question 1.
Find the HCF of te following numbers:
A. 18, 48
B. 30, 42
C. 18, 60
D. 27, 63
E. 36, 84
F. 34, 102
G. 70, 105, 175
H. 91, 112, 75
I. 18, 54, 81
J. 12, 45, 75
A.
Factors of 18 = 2x3x3
Factors of 48 = 2x2x2x2x3
HCF ( 18, 48) = 2×3 = 6
B.
Factors of 30 = 2x3x5
Factors of 42 = 2x3x7
HCF (30, 42) = 2×3 = 6
C.
Factors of 18 = 2x3x3
Factors of 60 = 2x2x3x5
HCF (18, 60) = 2×3 = 6
D.
Factors of 27 = 3x3x3
Factors of 63 = 3x3x7
HCF (27, 63) = 3×3 = 9
E.
Factors of 36 = 2x2x3x3
Factors of 84 = 2x2x3x7
HCF (36, 84) = 2x2x3 = 12
F.
Factors of 34 = 2×17
Factors of 102 = 2x3x17
HCF (34, 102) = 2X17 = 34
G.
Factors of 70 = 2x5x7
Factors of 105 = 3x5x7
Factors of 175 = 5x5x7
HCF (70, 105, 175) = 5X7 = 35
H.
Factors of 91 = 7×13
Factors of 112 = 2x2x2x2x7
Factors of 49 = 7×7
HCF (91, 112, 49) = 7
I.
Factors of 18 = 2x3x3
Factors of 54 = 2x3x3x3
Factors of 81 = 3x3x3x3
HCF (18, 54, 81) = 3×3 = 9
J.
Factors of 12 = 2x2x3
Factors of 45 = 3x3x5
Factors of 75 = 3x5x5
HCF (12, 45, 75) = 3

Question 2.
What is the HCF of two consecutive :
A. numbers?
B. even numbers?
C. odd numbers?